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新托福考试辅导_More Complex Stoichiometric Calculations
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= 0.27 moles HCl.
    Now, knowing that 1 mole of baking soda reacts with 1 mole of NaCl, we next need to figure out how many grams of baking soda would react with 0.27 moles of baking soda: 0.27 moles134 g/mol baking soda = 37.2 grams/mole NaHCO3
Molar mass (85.32) (36.46)
Balanced equation NaHCO3 + HCl NaCl + H2O + CO2
No. moles 0.274 10.0/36.46 = 0.274
Amount 0.27485.32 = 23.4 g 10.0 g

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