Next, we need to see how much energy would be needed to raise the temperature of water from 0ºC to 25ºC. The specific heat for liquid water is 1.00 cal/g ºC. So again use
energy = mCp DT to get energy = (10.0 g) (1.00 cal/g ºC) (25.0ºC) = 250 cal
Finally, add together all of the energies to get the total: 48.5 + 800 + 250 = about 1100 calories are needed to convert the ice to water at these given temperatures.
