To solve this problem, we need to resolve the force on the second rope into its northward and westward components.

 

 

    Because the force is directed 30º west of north, its northward component is

 

    and its westward component is

 

    Since the eastward component is also 2.0N, the eastward and westward components cancel one another out. The resultant force is directed due north, with a force of approximately 3.4N.

 

    You can justify this answer by using the parallelogram method. If you fill out the half-completed parallelogram formed by the two vectors in the diagram above, you will find that the opposite corner of the parallelogram is directly above the corner made by the tails of those two vectors